Load Balancing When m (nlogn): the max load is(with high probability P3:X≥0∑PX≥≤月 i=1 So we need P(Xi≥t)≤之 x≥≤(）()s()'() -()》= let t 4m/n 41g(n) 1Load Balancing let m=nlg(n) let t = 4m/n = 4lg(n)