由几何方程得: (1+/)2+B(1-3)+2(1-)hnr]+2(1-)C ar E 则=(+)3+(3-)B+2(1-)Bhr+2(1-1)C(a) r ro E auau u 0 a6 ar 由(a)第一式积分: l={-(1+1)2+B(1-3)y+2(1-)r(hr-1) E +2(1-12)Cr}+f() b) 由(a)第二式,将(b)带入,整理:由几何方程得: 0 1 [ (1 ) (3 ) 2(1 ) ln 2(1 ) 1 (1 ) [(1 3 ) 2(1 )ln ] 2(1 ) 1 2 2 − = + = − + + − + − + − + = + + − + − + − r u r u u r B B r C r A r E u r u B r C r A r E u r r (a) 由(a)第一式积分: 由(a)第二式,将(b)带入,整理: = − (1+ ) + [(1− 3 ) + 2(1− ) (ln −1)] 1 B r r r r A E ur 2(1 ) ( ) + − Cr + f 1 (b)