R4 10ko o U 61 2k2 i2 R2-6kQ (a) 15k对 V=10 sin t(mV (b) 2100k 1=0.6V0 30k 50k io) v2=0.8V0 33k (©) 图题2.3.2 (10sin ont)mV-150sin of(mV) (10sin at mV/1 k=10sin a(nA) 4=元=-150g0V:-30sna(kA) 5 kn 元。=i-i2=(-30 sin t-10 sin t)(μA) =-40 sin t(μA) 4