k dt dt kicAc k k k 3 0 3 理 k k 3 3 1( 3 -30 ) 同理 ( 3 -31 ) 1 2 ( ) 1 0 1 2 1 0 ( ) 0 1 0 0 ( ) 1 0 1 21 2 1 2 k k k c e k k k c c dc k c e dt k c e dt dc A k k t A B k k t t A c B k k t A B B + + + = − = = − +− + − + A k k t B e k k k c c ( ) 1 2 1 0 1 2 1 − + + + = A k k t C e k k k c c ( ) 1 2 2 0 1 2 1 − + − + =