【4-9】 (1)12( 99 i,2Q2 2 5 69 52 cQu 设Ln=10V,则 +i3=9.367A =9i1+un1=120.1v 12V 放当u=5V时 i4=12/5=2.4AUc=(5/120.1)×10=0.416 3.4A 7ig+un2=35.8V i2=an1/6=5.967A 心【4－9】 9 6 7 5 2 10 uoc + - i1 i2 i3 i4 i5 设uoc = 10 V，则 i5 = 1 A un2 = 12 V i4 = 12/5 = 2.4 A i3 = 3.4 A un1 = 7i3 + un2 =35.8 V i2 = un1 /6 = 5.967 A i1 = i2 + i3 =9.367 A us = 9i1 + un1 = 120.1 V 故当us ＝5V时 Uoc =(5/120.1)×10=0.416 V (1) (2)