习题 2解: (1)(AX)=4780H (2)(AX)=(4780H) (3)(AX)=(0450H+0210H) (3)(AX)=(4780H+0210H) (0660H) =(4990H) (注:(4780H)代表4780H单元中的值) 3解: (1) MOV AX 2000H 立即寻址方式 (2) MOVAX.[2000H直接寻址方式,PA=(DS产16+2000H=32000H (3) MOV DX. [BPI 寄存器间接寻址方式,PA=SS)*16+(BP=10020H (4) MOV BX[BX+S基址变址寻址方式,PA=①DS)*16(BX±(SD=30C1OH (5) ADD AX, ES: [BX]寄存器间接寻址方式,PA=(ES)*16+(BX=25200H (6) MOV CX VAX 直接寻址方式,BA=OS)16+0020H=30020H (7) AND AX BX 寄存器寻址方式 (8) MOV AX VAX(BXISI 相对基址变址寻址方式,PA=CDS16+VAX(BXH(SD=30C30H23 习题一