例242 b 5 3 400 0 0xs1001/40-13/4011/4-1 4x42002 10 5x,100-3/4111/400-3/41 13004.2555.75400.251 -3.250-2.7500-0.25-1 x,x3为非基变量 所以∞≤Ac1≤3.25 ≤C1≤4.25 0≤4c2≤275,-∞≤C3≤5.757 例2.4.2 x1 x2 x3 x4 x5 x6 x7 CB XB b 1 5 3 4 0 0 0 0 x5 100 1/4 0 -13/4 0 1 1/4 - 1 4 x4 200 2 0 - 2 1 0 1 - 1 5 x2 100 -3/4 1 11/4 0 0 -3/4 1 1300 4.25 5 5.75 4 0 0.25 1 cj - zj -3.25 0 -2.75 0 0 -0.25 - 1 2.75, 5.75 3.25, 4.25 , 3 3 1 1 1 3 − − − − c c c c x x 所以 为非基变量