2015/10/21 ME369-系统模型、分析与控制 6.5系统自由响应 School of Mechanical Engineering ME369-lecture 6.5 Shanghai Jiao Tong University Fall 2015 阶系统的自由响应 少+ay=0 y(0)=A 特征方程 S+a=0 yie(t)）=Aeam a>0 4=0 a<0 Time (f) Time(f) Time (f) School of Mechanical Engineering ME369-lecture 6.5 Shanghai Jiao Tong University Fall 2015 12015/10/21 1 ME369-lecture 6.5 Fall 2015 School of Mechanical Engineering Shanghai Jiao Tong University 6.5 系统自由响应 ME369-系统模型、分析与控制 ME369-lecture 6.5 Fall 2015 School of Mechanical Engineering Shanghai Jiao Tong University 一阶系统的自由响应 y ay   0 y A (0)  ( ) at free y t Ae  特征方程 s a   0