作业:(第七章数组) 1.求字符串“abn0O12的长度为 2.若一个二维数组a[7]8则该数组中任意一个元素a[订]在数组中 的位置公式为 3.求一下程序结果 no {inta8}{6,12,18,42,44,52,67,94}; int low=0, mid high=7, found,x found nf(%,, &x while( low<=high&&found==0) mid=(low+high )/2 if(x>a mid low=mid+1 else if (x<amid high=mid else found=l; break; if(found==1) printf( " Search successful! The index is: %d \n,, mid) printf( Cant search! n); 若运行时输入 则结果为作业:（第七章 数组） 1. 求字符串“ab\n\012\\”的长度为 2. 若一个二维数组 a[7][8],则该数组中任意一个元素 a[i][j]在数组中 的位置公式为 3. 求一下程序结果 main() { int a[8]={6,12,18,42,44,52,67,94}; int low=0, mid, high=7, found, x; found=0; scanf(“%d”,&x); while(low<=high&&found= =0) { mid=(low+high)/2; if (x>a[mid]) low=mid+1; else if (x<a[mid]) high=mid-1; else { found=1; break; } } if(found= =1) printf(“Search successful!The index is:%d\n”,mid); else printf(“Can’t search!\n”); } 若运行时输入: 52 则结果为