Sperner's Theorem Fc2 is an antichain.Then F≤(ny2) Lubell's proof(double counting) >lS1(n-IS)I≤nd S∈F IS(m-1S1)! n! ≤1 S∈F F1≤(2〉Sperner’s Theorem F 2[n] is an antichain. Then |F| ⇥ n n/2⇥ ⇥ . |F| n n/2⇥ ⇥ = 1 |F| n n/2⇥ ⇥ Lubell’s proof (double counting) SF |S|!(n |S|)! ⇥ n! ⇤ SF 1 n |S| ⇥ SF |S|!(n |S|)! n!