证:Ax=A xr≥xs|=max|x (-amr)xr=∑ J≠r (-sx=∑xj ≠S (1)xs=0→x=0,t≠r,t∈N→=ar →∈O (2)x3≠0→|x图x>0 (-am)(1-as)xrxs=∑ mrj i∑as ≠F ≠S返回 证: T n Ax x, x (x , x , , x ) =  = 1 2  | | | | max | | t t r xr xs x   = − =  jr arr xr arj x j ( ) − =  js ass xs asj x j ( ) (1) = 0 s x 0, , x t r t N t =    = arr  Ors − − =    js sj j j r ( arr )( ass)xr xs arj x j a x (2)  0 s x | xr || xs | 0