To conclude 2 ●●● ●●●● ●●●●● ●●●0 For Wilkinson power divider:G T.=(-1T=(2L-1)T ●●●●0 21 (21 ●●●● ●●●● ● §3.7 Dynamic Range F-2L@To Nonlinear device %=(a+2a,)+(a%+4a6)cos@w1 or 43<0 network coscos3 10 P(referred to output) ldB IdB compression point 3 -10 Slope =I 6263646 -30 -20-10 0 1020 (dBm) EXAMPLE 3.5,page 92. 2To conclude - 2 §3.7 Dynamic Range For Wilkinson power divider: EXAMPLE 3.5, page 92. 2 21 1 2 G L  21 1 ( 1) (2 1) T T LT e G    0 F  2 @L T 0 Nonlinear device v or vi network   2 0 0 20 0 2 3 1 3 20 0 30 0 0 30 1 ( ) ( )cos 2 1 1 cos 2 cos 2 4 3 3 4 v a aV t a aV t t V V a a V           3 a  0