33.5 Crystal Structure of Ceramic Materials AB AB, A2B3 ABO3 AB,Oa Ab type N CI 1. NaCl r/r-=0.54 octahedron =>CN+=6 NaCl Z=1=CN(ZCN)=CN×1/6 .CN=6§3.5 Crystal Structure of Ceramic Materials AB AB2 A2B3 ABO3 AB2O4 ◆Ⅰ. AB type 1. NaCl r + /r－＝0.54 ∴ octahedron ＝> CN+＝6 Z－＝1＝CN－(Z + /CN+ )＝CN－×1/6 ∴ CN－＝6