QUESTION 4 (Continued) k (0.5×0.11)+0.5×0.105 =0.05750.053 =0.1105 os,-Ww1o1+ w202+2w,w2.9,02 √0s×00390+5×042)+(2×050.5030.03908042 =√0.00038126.0004410.00024651 √0.00106826 0.0327July 200 3 QUESTION 4 (Continued) ( ) ( ) = 0 .1 1 0 5 = 0 .0 5 7 5+ 0 .0 5 3 = 0 .5 0 .1 1 5+ 0 .5 0 .1 0 6 k = w k n j =1 p j j     ( ) ( ) ( ) 0 .0 3 2 7 = 0 .0 0 1 0 6 8 2 6 5 = 0 .0 0 0 3 8 1 2 5 + 0 .0 0 0 4 4 1+ 0 .0 0 0 2 4 6 0 1 5 = 0 .5 0 .0 3 9 0 5+ 0 .5 0 .0 4 2 + 2 0 .5 0 .5 0 .3 0 .0 3 9 0 50 .0 4 2 = w + w + 2 w w r 2 2 2 2 1 2 1 , 2 1 2 22 22 21 2 k 1 p =            