Thus. [HgOg OH)]=1.0x10- Or H]=1.0x10 [H,Otaa】 But the total negative charge must equal the total positive charge: [H,Oia】=[oHa】+[Ctaa】 H,0J=1.0x10 以O+2.0x10, [H,0a2-2.0×10-H,01】-1.0×104=0 H,0]=20x10'±2.0x10y-40-1.0x105 2(0 2.0×10-7±2.83×10-7 =2.41x10-70r-4.15×10-8 pH=-log1oH,0aa】=-logo(2.41×10-7)=6.62 C3(a).What volume of fluorine gas,measured at STP,is produced by electrolysis of molten KF using a current of 10.0 A for 2.00 hours? KF0→K+F 2F→F2+2e it =nF n=其-10.0Cs'2.00×3600s F- 96,487Cmo -0.746mole 1mol F2=0.373 molFa0) 0.746mole×2mole 0.373molF2g 22.4L=8.36 mol at STP mol C3(b).What mass of potassium metal is produced in this same reaction? K*+e→Ke 0.746 mol e>0.746 mol Kis)Thus, 14 3 (aq) (aq) 14 (aq) 3 (aq) [H O ][OH ] 1.0 10 or 1.0 10 [OH ] [H O ] + − − − + = × × = − But the total negative charge must equal the total positive charge: 3 (aq) (aq) (aq) 14 7 3 (aq) 3 (aq) 2 7 14 3 (aq) 3 (aq) 7 7 2 3 (aq) 7 7 7 [H O ] [OH ] [Cl ] 1.0 10 [H O ] 2.0 10 [H O ] [H O ] 2.0 10 [H O ] 1.0 10 0 2.0 10 (2.0 10 ) 4(1)( 1.0 10 ) [H O ] 2(1) 2.0 10 2.83 10 2 2.41 10 or 4.15 + −− − + − + + − + − − − + − − − = + × = +× −× −× = × ± × − −× = ×± × = =× − 8 7 10 3 (aq) 10 10 pH log [H O ] log (2.41 10 ) 6.62 − + − × = − =− × = −14 C3 (a). What volume of fluorine gas, measured at STP, is produced by electrolysis of molten KF using a current of 10.0 A for 2.00 hours? KF(l) → K+ + F- 2 F- → F2 + 2 e￾it = nF 1 1 2(g) 2(g) 2(g) 2(g) it 10.0 C s (2.00 3600)s n F 96,487 C mol 0.746 mol e 1mol F 0.746 mol e 0.373 mol F 2 mol e 22.4 L 0.373 mol F 8.36 mol F at STP mol − − − − − × = = = × = × = C3 (b). What mass of potassium metal is produced in this same reaction? K+ + e- → K(s) 0.746 mol e- → 0.746 mol K(s)