Example:lfh1=1200,h12=0.0002,h2=50,h220.00005. Findz andz out· Solution: 10-3-800/1=1200I1+2×10-V 800 500(2=)-V2/500501+50×10v 1∠0°m④ 0.001=2000I1+0.0002V 0=50I1+0.00025V2 丿1=0.592n 172 1=0.5101 40 102n I2=20.44 200011 =1160g 0.0002 22.4kQ 丿s=0 2 20001 50/1+0.00005 0.0002Example: If h11=1200, h12=0.0002,h21=50, h22=0.00005S. Find Zin and Zout. Solution:     = − = +  − = +  • − • • • • − • • − 2 6 2 2 1 2 4 1 1 3 ( ) / 5000 50 50 10 10 800 1200 2 10 I V I V I I V     = + = + • • • • 1 2 1 2 0 50 0 00025 0 001 2000 0 0002 I . V . I . V or     = − = • • V mV V mV 102 0.592 2 1     = = • • I A I A   20.4 0.510 2 1 172 1 2 • = − • V V 40 1 2 • = • I I = • =  • 1160 1 1 I V Zin =  + − − = = = • • • • • • k I I I V s I V Zout 22.4 ) 0.0002 2000 50 0.00005( 0.0002 2000 0 1 1 1 2 2 5000 − + • V 2 I 2 • I 1 • − + • V 1 − + 800 1 0 mV  