普通最小二乘法 Ordinary least squares procedure) 求b和b使残差平方和最小 ∑c=∑(x-1)=∑y-(+bx Let x,=X-X and y=YY Then b=∑x/∑ Xi (OLSE) -Y-bX普通最小二乘法(Ordinary least squares procedure): 求 使残差平方和最小: Let Then (OLSE) 0 1 b b 和 2 2 2 0 1 ˆ ˆ ˆ ( ) [ ( )] i i i i i    e Y Y Y b b X = − = − + and i i i i x X X y Y Y = − = − 2 1 0 1 ˆ ˆ ˆ i i i b x y x b Y b X  =   = −  