If we are given the initial value have i as i, (0 then i2(0)= R1i(0+) R i1(0)=i1(0+) R3 /i(0+)+i2(0+ R4 R2 R4 R 2 R1+R2i(0) R i1(t)=i1(0+)e 2()R i1(0+)e ()=-R+R, i1(0+)e (t=L/Rea) R Since the inductor current decays exponentially as e t, then every current and voltage in the resistive network must have the same function behavior( ) (0 ) ( / ) 1 2 1 2 eq t L i e L R R R R and i t = + = − − +   2 1 1 2 (0 ) (0 ) R R i then i + + = i ( ) R R R [i ( ) i ( )] i ( ) i ( ) L L + + + + + = − = − + = 0 0 0 0 0 1 2 1 2 1 2   t t i e R R i t i e i t − + − +  ( ) = (0 ) ( ) = (0 ) 1 2 1 1 1 2 If we are given the initial value have i1 as (0 ). 1 + i Since the inductor current decays exponentially as , then every current and voltage in the resistive network must have the same function behavior.  t e −