Pre-Laboratory Question: 1.Two kinetics runs are performed at the same temperature withS held constant and thein the first run being four times that in the second.Ifthe change in the concentration is 5x10M of S,and the reaction times are 20 seconds(Run 1)and 82 seconds(Run 2) what is theorder with respect to iodideon? 2.How cou on determine that the Cuionin the catalyst is the active species,rather than the nitrate ion? 3.Explain why the relationship M(S()molS 4「S,01= 2molS,O is correct. Name: Data: Section: PDF文件使用”pdfFactory Pro”试用版本创建wmw,fineprint..com,cnPre-Laboratory Question: 1. Two kinetics runs are performed at the same temperature with 2 S O2 8 - é ù ë û held constant and the [I-] in the first run being four times that in the second. If the change in the concentration is 5×10-5M of 2 S O2 8 - é ù ë û , and the reaction times are 20 seconds (Run 1) and 82 seconds (Run 2), what is the order with respect to iodide ion? 2. How could one determine that the Cu2+ ion in the catalyst is the active species, rather than the nitrate ion? 3. Explain why the relationship 2 2 2 2 8 2 3 2 3 2 2 2 8 2 8 total 1molS O (S O ) (S O ) 2molS O S O M V V D - - - - - × é ù = ë û is correct. Name:_______________________________________________________________________ Data:___________________ Section:______________________________________________ PDF 文件使用 "pdfFactory Pro" 试用版本创建 www.fineprint.com.cn