TABLE 4.1: Can both r1 and r2 be Sct to O? Core cl Core c2 Comments SI: x= NEW: S2: y=NEW: /* Initially,x=0&y=0*/ LI: rl=y L2:2=x S2: y= NEW: P NEW" L2:r2=X/0 SI:X=NEW: F NEW #/ rl=y: / NE Outcome:(rl, r2)=(NEW. 0) (c)TSo SC Execution 3 SI: X= NEW:/ NEW 5 S2:y=NEW;/NEW考 L:rl=y;/*0制 L2:n2=x/0” Outcome: (rl, r2)=(0, 0) (d) TSO Execution, but NOT an SC Execution RE 4.2: Four alternative tso Executions of table 4.I's program 2021/2/11 计算机体系结构2021/2/11 计算机体系结构 12