#include <stdio .h> void maino dint i, k=0 printf("\n) for(=1;i<=200;++) f(9%2==0) i printf( %/5d",ii k+十 f(k%10==0) printf("n;#include <stdio.h> void main() { int i,k=0; printf("\n"); for(i=1;i<=200;i++) if(i%2==0) { printf("%5d",i); k++; if(k%10==0) printf("\n"); } }