Date 解:0取FD为离 & kN 个作 个 3m 2MF=0 6+8×3=0 KN (v) 2 作x6-8×3 =4NC个) 2×=0×-×4-8=0(0 取FED为陌离纳 YD 2MD =0 Fx3-4X3=0 F=4NC>)〓 代入Q)式中×6 6三-9N() AFC白B为隔纳 2MA=08×6+4x3+4x6+4×3=0 个 YB=-然kN() 又M8B=0YAx6-4×6-4 A=8k(个 2×=0xA-X8-4-4=0(b) @取AFC隔禽