4.From the velocity triangle we have: Velocity scale factor: h=5-inseeI in VB=3.438.in-ky B=17.190n 0B=59deg sec VBA:=4.784m-k 'BA=23.920n 0BA=38.deg sec 5.Determine the angular velocity of link 3 using equation 6.7. -VBA 03= b o3=-13.289ad sec 6.Determine the magnitude and sense of the vector Vc using equation 6.7. VcA;=p03 'cA=19.136m sec 日c4:=(128-49-90)deg 0c4=-11.000deg 7.Use equation 6.5 to (graphically)determine the magnitude of the velocity at point C.The equation to be solved graphically is VC=VA+VCA a.Choose a convenient velocity scale and layout the known vector VA. b.From the tip of V,layout the (now)known vector Vc4. c.Complete the vector triangle by drawing Vc from the tail of V to the tip of the Vc vector. 0 5 in/sec LLL⊥L」 Y 1.902 N X 11.000° 22.572° 3.827- VCA 8.From the velocity triangle we have: Velocity scale factor: 元=5mecl in Vc=1.902 in-ky 'c=9.510n 0c=-22.572deg sec