概華论与款程统外 b=-(2nr+z212)=-(2c+z2)=-123.84, c=nX2=nx2=36, 于是p,=-b-vb-4ac =0.50, 2a D:=b+ac 20 =0.69, p的置信水平为0.95的置信区间为(0.50,0.69). (2 ) 2  / 2 b = − nX + z (2 ) 2  / 2 = − nx + z = −123.84, 2 2 c = nX = nx = 36, a b b ac p 2 4 2 1 − − − 于是 = a b b ac p 2 4 2 2 − + − = = 0.50, = 0.69, p 的置信水平为0.95的置信区间为 (0.50, 0.69)