Solutions continued 2) p2=(751.4×133.32+30×9.81)Pa K=2rs63.81m Far distance Po T2 3) p3=P1 T=(273.15+30)K Summer =2hrs61.16m Po T Note: Gas:volume changes with (p,T).If using Vas a quantity measure,conditions should be specified. As long as the pressure is low,any gas could be treated as ideal gas.Sometimes R is unknown,but doesn't matter.It could be canceled when applying the standard conditions to the problem. 上游充通大 March 21,2018 11 HANGHAI JLAO TONG UNIVERSITYMarch 21, 2018 11 2） 2 2 0 3 0 0 2 (751.4 133.32 30 9.81) Pa 63.81 m p p T V V p T       3） 3 1 3 3 0 3 0 0 3 (273.15 30) K 61.16 m p p T p T V V p T      Note: • Gas: volume changes with (p,T). If using V as a quantity measure, conditions should be specified. • As long as the pressure is low, any gas could be treated as ideal gas. Sometimes R is unknown, but doesn't matter. It could be canceled when applying the standard conditions to the problem. Solutions continued Summer Far distance