Cp△t=(04×18×4×78+0.6×184×92)(95-20 11925kJ/kmol y=(0.4×93×78+0.6×86×92)×4.18 31972k/ kmol q=(11925+31972)/31972=137 q线方程 q 1.37 0.4 137-1137-13.7x-10810 Cp△t = ( 0.4×1.8×4×78 + 0.6×1.84×92)(95 - 20) = 11925 kJ / kmol γ = ( 0.4 × 93 × 78 + 0.6 × 86 × 92 ) × 4.18 = 31972 kJ / kmol q = ( 11925 + 31972 ) / 31972 = 1.37 q 线方程: 1 −1 − − = q x x q q y F 1 37 1 0 4 1 37 1 1 37 − − − = . . x . . = 3.7x −1.08