Example 45.1 Given: Air Standard Otto Cycle: r=8,V=560cm3 state 1:p1=1 bar,T1=300K state 3:T3=2000 K Find: Pressures,temperatures and specific volumes at all state points Heat input,net work output and thermal efficiency ·MEP P,kPa T3=2000K Assumptions: (1)air-standard assumptions Isentropic (2)△KE=0,△PE=0 v=const. Solution: out v=const. Isentropic 100 P1=1bar,T1=300K U2=U3=8U1 U1=v4 ·r=8,V=560cm3 上游充通大率 May15,2018 18 SHANGHA BAO TONG LINIVERSITYMay 15, 2018 18 Example 45.1 Given: • Air Standard Otto Cycle: r = 8, V = 560 cm 3 state 1: p 1 =1 bar, T 1 =300 K state 3: T 3 = 2000 K Find: • Pressures, temperatures and specific volumes at all state point s • Heat input, net work output and thermal efficiency • MEP Assumptions: (1) air‐standard assumptions (2) KE=0, PE=0 Solution: • r = 8, V = 560 cm3 p1 =1 bar, T1 =300 K T3 = 2000 K