H2+Cl2-→2H+2CI E=E°-RLn 2F (PPPc IP) =E0 F (D41p)2(P,1p)2 1 H2+ 1 Cl2→H++C1 2 2 E=E°-RLn arracr (Pu,/P)2(P,/p)2 2727 H2 + Cl2 —→ 2H+ +2Cl- + − H + Cl ⎯→H +Cl 2 2 2 1 2 1 2 ( / )( / ) 0 0 2 2 0 2 2 P P P P a a Ln F RT E E H Cl H Cl + − = − 2 1 2 0 1 0 0 ( / ) ( / ) 2 2 P P P P a a Ln F RT E E H Cl H Cl + − = − 2 1 2 0 1 0 0 ( / ) ( / ) 2 2 P P P P a a Ln F RT E H Cl H Cl + − = −