ch657 p(t>ta=a ta =t- n=10 0.15 0.05 P(T>18125)=0.05210(10)=18125 P(T<-1.825)=00,P(7>-18125)=095 →1095(10)=-1.8125ch6-57 -3 -2 -1 1 2 3 0.05 0.1 0.15 0.2 0.25 0.3 0.35 n = 10 ( )     − = −  = 1 t t P T t ( ) 0.05 P T t  =  = 1.8125 0.05 (10) 1.8125 t -t • • P T P T (  − =  − = 1.8125 0.05, 1.8125 0.95 ) ( )  (10) 1.8125  t 0.95 = −