正在加载图片...
Dayu Wu Applied Statistics Lecture Notes Estimation:MLE 1.Y~N(XB,o21) 2.L=(2m)(a2)-号exp{-a(Y-x8)Ty-1(Y-X3)} Propositions 1.B=(Xx)-XTY 2.E(③=B 3.Var(3)=a2(xrx)-1 4.Gauss-Markov:E(Y)=XB,Var(Y)=a2I 5.Co(a,e)=0 6.Y~N(XB,o21) 7.~N(8,o2(xx)-1) 8.要~X品-p-1 Test 1.:A=…=R=0,F=s心Fp,n-p-1) 2.:属=0,5=易心np- 3.E=号 4.(1-a)CI of:(间-ta2Vcd,+ta2√c Standardization 1场=密 2所=品 3财== Correlation 1.r= 2.r2=5Ee 5of6Dayu Wu Applied Statistics Lecture Notes Estimation: MLE 1. Y ∼ N(Xβ, σ2 In) 2. L = (2π) − n 2 (σ 2 ) − n 2 exp{− 1 2σ2 (Y − Xβ) TΣ −1 (Y − Xβ)} Propositions 1. βb = (X TX) −1X TY 2. E(βb) = β 3. V ar(β) = σ 2 (X TX) −1 4. Gauss-Markov: E(Y) = Xβ, V ar(Y) = σ 2 In 5. Cov(β, e b ) = 0 6. Y ∼ N(Xβ, σ2 In) 7. βb ∼ N(β, σ2 (X TX) −1 ) 8. SSE σ2 ∼ χ 2 n−p−1 Test 1. H0 : β1 = · · · = βn = 0, F = SSR/p SSE/(n−p−1) ∼ F(p, n − p − 1) 2. H0 : βj = 0, tj = βcj √cjjσb ∼ tn−p−1 3. Fj = t 2 j 4. (1 − α) CI of βj : (βbj − tα/2 √cjjσ, b βbj + tα/2 √cjjσb) Standardization 1. x ∗ ij = x√ ij−x¯j Ljj 2. y ∗ i = √ yi−y¯ Lyy 3. β ∗ j = √ Ljj √ Lyy βbj Correlation 1. r =   1 r12 . . . r1n r21 1 . . . r2n . . . . . . . . . . . . rn1 rn2 . . . 1   2. r 2 y1;2 = SSE(x2)−SSE(x1,x2) SSE(x2) 5 of 6
<<向上翻页向下翻页>>
©2008-现在 cucdc.com 高等教育资讯网 版权所有