The Coefficient of Performance(COP)is used to measure the effectiveness of the heat pump COP=Q/=Q/(Qn-Qc)=T/(Th-Te Example: Calculate the ideal COP for an air-to-air heat pump used to maintain the temperature of a house at 21oC when the outside temperature is -1C Solution h=219C=294K 6=-10C=272K COP=T(Th-T=294K(294K-272K=13.3 Thus, for each watt of power used to drive this heat pump, 13.3 watts are delivered to the hot reservoir( the interior of the house), and 12.3 watts are extracted from the cold reservoir( the outside the house). In practice, the coP for such a situation would be much less favorable(in the range of26)The Coefficient of Performance (COP) is used to measure the effectiveness of the heat pump. COP = Qh /W = Qh /(Qh – Qc ) = Th /(Th – Tc ) Calculate the ideal COP for an air-to-air heat pump used to maintain the temperature of a house at 21oC when the outside temperature is -1 oC. Solution Th = 21oC = 294 K Tc = -1 oC = 272 K COP = Th / (Th – Tc ) = 294K/(294K – 272K) = 13.3 Thus, for each watt of power used to drive this heat pump, 13.3 watts are delivered to the hot reservoir (the interior of the house), and 12.3 watts are extracted from the cold reservoir (the outside the house). In practice, the COP for such a situation would be much less favorable (in the range of 2-6). Example: