Chapter 6 Problem solution 6.23 Shown in Figure 6.23 is(jo)for a lowpass filter. Determine and sketch the impulse response of the filter for each of the following phase characteristics: HGo (a)∠H(jo)=0h()= sin o t t (b)ZHGjO=oT, where T is a constant sin a(t+T h() (+r) (c)∠H(o) 丌/2>0 丌/2<0 h(t) 2sin(ot 元t1 Chapter 6 Problem Solution 6.23 Shown in Figure 6.23 is for a lowpass filter. Determine and sketch the impulse response of the filter for each of the following phase characteristics: H(j) (a 0 ) = H j ( ) 0 1 −c H(j) c ( ) t t h t c sin = ( ) ( ) (t T ) t T h t c + + = sin (b) , where H(j)=T T is a constant. ( ) = / 2 0 / 2 0 -π (c) H j ( ) ( ) t t h t c 2sin / 2 2 − =