●●● Simple example using Conditional ●●●● ●●●●● ●●●● Probabilities ●●●●● ●●●● We toss a fair coin three successive times. We wish to find the conditional probability P(A B)when A and B are the events A=more heads than tails come up), B=(lst toss is a head y The sample space consists of eight sequences, Q=HHH, HHT, HTH, HTT, THH, THT, TTH, TTTH which we assume to be equally likely. The event B consists of the four elements HHH, HHT, HTH, HTT, so its probability is 4 P(B) The event An B consists of the three elements outcomes HHH, HHT, HTH, so its probability is P(A∩B) Thus, the conditional probability P(AJB)is P(A/B)=P(AnB)3/8_3Simple Example using Conditional Probabilities