N2(g)+3H2(g)→>2NH(g) 时ng2/mol3.010.0 0 0 t1时nB/mol207.0 2.0 51 t2时np/mol1.55.5 3.0 A∥5=△nCN)=(20-30)m0=10my △n(H2)(70-100mol l Mol 51= △n1(NH2)(2.0-0)mol =1mol NH 52=15molN (g) 3H (g) 2NH (g) 2 + 2 → 3  t0时 nB /mol 3.0 10.0 0 0 t1时 nB /mol 2.0 7.0 2.0 t2时 nB /mol 1.5 5.5 3.0 1   2 ( ) ( ) 1.0mol 1 (2.0 3.0)mol N N 2 1 2 1 = − − =  =   n 1.5mol  2 = ( ) ( ) 1.0mol 2 (2.0 0)mol N H N H 3 1 3 1 = − =  =   n ( ) ( ) 1.0mol 3 (7.0 10.0)mol H H 2 1 2 1 = − − =  =   n