Using the Hip and slide method to perform the convolution, we see that the product of the two signals(based on overlap)is first non-zero at t=-T1-T2 and it stops being non-zero at t=1+T2. Thus, the output, y(t)is zero for t>T1+ T2 Generally, when convolving two CT signals of finite duration, the result starts being non-zero at the sum of the time indices when the two original signals start being non- zero. Similarly, the result of the convolution ends being non-zero at the sum of the time indices when the signals to be convolved end being non-zeroUsing the flip and slide method to perform the convolution, we see that the product of the two signals (based on overlap) is first non-zero at t = −T1 − T2 and it stops being non-zero at t = T1 + T2. Thus, the output, y(t) is zero for |t| > T1 + T2. Generally, when convolving two CT signals of finite duration, the result starts being non-zero at the sum of the time indices when the two original signals start being non￾zero. Similarly, the result of the convolution ends being non-zero at the sum of the time indices when the signals to be convolved end being non-zero. 5