根据 △，G°=-2.303 RTlgK8 g邮& △G 27.1×103J-mol-1 2.303RT 2.303×8.314J.K.mol-.298K =-4.75 K8=1.78×10-5 θ C θ 根据 Δr G = −2.303RTlgK 4.75 2.303 8.314J K mol 298K 27.1 10 J mol 2.303RT Δ G lgK 1 1 θ 3 1 θ r C = −       = − = − − − − θ 5 C K 1.78 10− = 