Stresses in Springs o Removed portion exerts force F and torsion T on remaining part Maximum stress in wire is: Tr F 十 max 士 A ·T=F*D/2=torque ·r=wire radius ·J=πd/32=polar moment of inertia A=wire cross-sectional areaStresses in Springs • Removed portion exerts force F and torsion T on remaining part • Maximum stress in wire is: max Tr F J A τ =± + • T = F ∗D/2 = torque • r = wire radius • J = π d 4/32 = polar moment of inertia • A = wire cross-sectional area