E(t,) E(t, to)=E(t, to)+U E(t20) (Rcu-r2) R Ru(to=rcu(to[l+a(to-to) 如果满足:R2=R(t) RC R2 则:U 事实上E(t,()和E(t2)的差值可以近似为:E(,t)E(t,t0)=B(t-t4) 如果使:R(t)xn(b-t0)/=B(t2-t) 即:R(1(t0)1I=B 可以满足冷端温度补偿 补偿电阻的阻值R(t)取决于:a、、R1 R1 RCu R2 0 E(t,t) 0 E(t,t ) I I a b 0 0 ( , ) ( , ) E ab t t E t t U 2 ( ) Uab Cu I R R 0 0 0 0 0 ( ) ( )[1 ( )] RCu Cu t t R t t t 2 0 ( ) R RCu 如果满足: t 0 0 0 0 ( ) ( ) Uab Cu t 则: IR t t t 0 0 事实上E(t,t )和E(t,t)的差值可以近似为: 0 0 0 0 E(t,t)-E(t,t )= (t t ) 0 0 0 0 0 0 ( ) ( ) ( ) RCu t 如果使: t t t I= t t 0 0 ( ) RCu t 即: t I 可以满足冷端温度补偿 0 0 ( ) RCu t 补偿电阻的阻值 t 取决于: 、I、