Example 5.3.4 k G(SH(S=- (s+1)2(s+1+18s+1-j18 across tie miami points s4+4s3+24s2+40s+19+k=0 O 18 2419+k i3.16 40 Breakaway 3 14 19+k 484-4k 14 14s2+140=0 19+ks=±j3.16 3. × 18 4844k=0ge=1212021/1/26 9 3. Symmetry 4. No segments on real axis 6. Breakaway and break 5. Asymptote -in points 7.The point where the locus across the imaginary axis Example 5.3.4: 1. Find poles and zeros -1 2. 4 segments 1 4 1 1 1 1 1 1 = − + + + = − − − = −   = = n m p z n j m i j i    =    + = 45 135 4 180 (2 1) 或 k   1 1 3 3 12 10 0 0 [( 1) ( 1 18)( 1 18)] 1 2,3 3 2 2 Solutions s s j yields s s s ds d s s j s j = − = −  + + + = = + + + + − Breakaway s k k s s k s s k s s s s k + − + + + + + + + = 19 0 14 484 4 14 19 4 40 0 1 24 19 4 24 40 19 0 0 1 2 3 4 4 3 2 ( 1) ( 1 18)( 1 18) ( ) ( ) 2 s s j s j k G s H s + + + + − = 484-4 =0 get k k =121 14 140 0 2 s + = =121 s =  j3.16 -j3.16 k j3.16 k =121