拆分分母：Chebyshev多项式1+e2T()=0 即， ch(示。重 令，ch()=u+v chod(a chmu-cosm+jshnu-sin chnu.cosnv =0 1 shnusinnv=1 ( ) 0 2 2 拆分分母：Chebyshev多项式 + e Tn - js = [ ( )] e 1 1 ch nch - js = ± j - 即， 令， ch (- js) = u + jv -1 [ ( )] e 1 ch n u + jv = j e 1 chnu ×cos nv + jshnu ×sin nv = j ï î ï í ì × = × = e 1 sin cos 0 shnu nv chnu nv