Example2:(p175-12) A resistor R, capacitor C, and voltage source Ds =100 cos 300M 150W and the rms capacitor voltage is 10v, determine r andc a are all in series. If the average power dissipated by the resistor R Solution R=V70.72-104=70 100 R702 32702 150 70 3272.143 2.143 714uF 300×10A resistor R, capacitor C, and voltage source V are all in series. If the average power dissipated by the resistor is 150W and the rms capacitor voltage is 10V, determine R and C. t  s = 100cos300 70.7 10 70 2 2 VR = − = 2.143 32.7 70 I = = C 714uF 300 10 2.143 =  = 32.7 150 702 R = = R C − = +  s 100cos 300tVi Example 2:(p175-12) Solution: