劣溪享化学与分子科学学院 COLLEGE口F CHEMI5TRV月ND MOLECULRR5 CIENCE5 WUHAN UNIVERSITY 例计算pH4.00和8.00时HAc的δe、δAc 解：已知HAc的K2=1.75X105 pH=4.00时 δHAc= H灯 =0.85 H]+Ka δAc= K 0.15 [H]+K pH=8.00时 dHae=5.7X10-4,δAc≈1.0 或溪来等 Wuhan University 例 计算pH4.00和8.00时HAc的δHAc、δAc- 解: 已知HAc的Ka=1.75×10-5 pH = 4.00时 pH = 8.00时 δHAc = 5.7×10-4 , δAc- ≈ 1.0 [H+ ] δHAc = = 0.85 [H+ ] + Ka Ka δ Ac- = = 0.15 [H+ ] + Ka