圈上大峰 Torque Loading-Load Lowering3 (Loosening screw) (b) Summing the forces in vertical and horizontal directions gives ΣFH=-P-Nsin2+fN cosλ=0 ∑Fy=F-Ncosλ-fN sinλ=0 51 国上活大隆 Torque Loading-Load Lowering3 (Loosening screw) Eliminating the normal force gives: P=Ffcos-sin) (cos +fsin a) tan2=l/(元dm)- Dividing both numerator and denominator by cosλgives: p=FV-Wm】 1+(f/πdnm) 5251 Summing the forces in vertical and horizontal directions gives FH = -P - N sin  + f N cos  = 0 FV = F - N cos  - f N sin  = 0 Torque Loading-Load Lowering3（Loosening Screw） 52 Eliminating the normal force gives: tan  = l / ( dm). Dividing both numerator and denominator by cos  gives: Torque Loading-Load Lowering3（Loosening Screw）         cos sin cos sin f f P F          m m fl d F f l d P      1