(c) Express Pr(Bn+1=k)in terms of Pr(Bn= k)and Pr(Bn=k-1)assuming that 0<k< Pr(Bn+1=k) Solution Pr(Bn,=b⊥n-k Pr(B2+1=k) n+ k-1)Final Exam 9 (c) Express Pr (Bn+1 = k) in terms of Pr (Bn = k) and Pr (Bn = k − 1) assuming that 0 < k < n. Pr (Bn+1 = k) = Solution. k Pr (Bn+1 = k) = n − k Pr (Bn+1 = k) + Pr (Bn+1 = k − 1) n + 1 n + 1