●●●●● ●●●● 般DMc的容量计算 ●●0 ●●● ●●●● 信道转移矩阵是非奇异方阵,假定所有Q≥0 O=∑Qp(|k)j=01,K-1 k=0 ∑(|)bgp(|k)-∑i1)oga=Ck=01,,K-1 ∑(k)C+gO=∑m(1k)ogp(k)k=0.,1K-1一般DMC的容量计算 ⚫ 信道转移矩阵是非奇异方阵，假定所有Qk>0      − = − = − = − = − = + = = − − = = − = = − 1 0 1 0 1 0 1 0 1 0 ( | )[ log ] ( | )log ( | ) 0,1,..., 1 ( | )log ( | ) ( | )log 0,1,..., 1 ( | ) 0,1,..., 1 J j J j j J j j J j K k j k p j k C p j k p j k k K p j k p j k p j k C k K Q p j k j K   