C(石墨)+02(g)=C02(g) H393.5-kJ-mol-i (1) CO(g) +1/202(g)= C02(g) H=-283.0 kJ.mol-1 (2) (1)(2)得C(石墨)+1/202(g)=C0(g) △H9m △H9m=-393.5-(-283.0)=-110.5kJ-mo-1 ∴ C(石墨) + O2 (g) = CO2 (g) rH m = −393.5 kJmol-1 (1) CO(g) + 1/2O2 (g) = CO2 (g) rH m = −283.0 kJmol-1 (2) (1)− (2) 得 C(石墨) + 1/2O2 (g) = CO(g) rH m ∴ rH m = −393.5 − (−283.0) = −110.5 kJmol-1