第3章矩阵、数组和符号运算 x2+√2x+2=0 求非线性方程组x+32=4的解。 解: [x, y, z=solve( 2+sqrt(2)*x+2=0, x+3*4=4, y*Z-1,'x,yl,z) X [(-1/2+1/2*i*3^(12)*2^(12) [(-1/2-1/2*i*3^(1/2)*2^(1/2) [-51/73+3/73*1*3^(1/2)-27/146*(-12+112*1*3^(12)*2^(12)-3/146*2^(12 [-5173-373*i*3^(12)-27/146*(-1/2-1/2*1*3~(112)*2(12)-3/146*2(12 = [-1/3*(-12+1/2*1*3^(1/2)*2^(112)+4/3 [-1/3*(-1/2-12*1*3^(12)*2~1/2)+43]第3章 矩阵、数组和符号运算 求非线性方程组 的解。 解： [x,y,z]=solve('x^2+sqrt(2)*x+2=0','x+3*z=4','y*z=-1','x','y','z') x = [ (-1/2+1/2*i*3^(1/2))*2^(1/2)] [ (-1/2-1/2*i*3^(1/2))*2^(1/2)] y= [-51/73+3/73*i*3^(1/2)-27/146*(-1/2+1/2*i*3^(1/2))*2^(1/2)-3/146*2^(1/2)] [ -51/73-3/73*i*3^(1/2)-27/146*(-1/2-1/2*i*3^(1/2))*2^(1/2)-3/146*2^(1/2)] z = [ -1/3*(-1/2+1/2*i*3^(1/2))*2^(1/2)+4/3] [ -1/3*(-1/2-1/2*i*3^(1/2))*2^(1/2)+4/3]      = − + = + + = 1 3 4 2 2 0 2 yz x z x x