CHAPTER 2 ALKANES SOLUTIONS TO TEXT PROBLEMS 2.1 A carbonyl group is C=O. Of the two carbonyl functions in prostaglandin E, one belongs to the ketone family, the other to the carboxylic acids functional OH 2.2 An unbranched alkane(n-alkane)of 28 carbons has 26 methylene(CH,) groups flanked by a methyl (CH3) group at each end. The condensed formula is CH3(CH,)26CH3. 2.3 The alkane represented by the carbon skeleton formula has ll carbons. The general formula for an alkane is CnH,n+2, and thus there are 24 hydrogens. The molecular formula is ClH 4; the condensed structural formula is CH3(CH)CH 2.4 In addition to CH3 (CH2)4CH3 and(CH,)2CHCH,CHa CH3, there are three more isomers. One has a five-carbon chain with a one-carbon(methyl) branch CHa CH, CHCH, CH The remaining two isomers have two methyl branches on a four-carbon chain. H3 CH3 CHCHCH3 CH, CH, CCH3 Back Forward Main Menu TOC Study Guide Toc Student OLC MHHE Website25 CHAPTER 2 ALKANES SOLUTIONS TO TEXT PROBLEMS 2.1 A carbonyl group is C?O. Of the two carbonyl functions in prostaglandin E1 one belongs to the ketone family, the other to the carboxylic acids. 2.2 An unbranched alkane (n-alkane) of 28 carbons has 26 methylene (CH2) groups flanked by a methyl (CH3) group at each end. The condensed formula is CH3(CH2)26CH3. 2.3 The alkane represented by the carbon skeleton formula has 11 carbons. The general formula for an alkane is CnH2n2, and thus there are 24 hydrogens. The molecular formula is C11H24; the condensed structural formula is CH3(CH2)9CH3. 2.4 In addition to CH3(CH2)4CH3 and (CH3)2CHCH2CH2CH3, there are three more isomers. One has a five-carbon chain with a one-carbon (methyl) branch: The remaining two isomers have two methyl branches on a four-carbon chain. CH or or 3CHCHCH3 CH3 CH3 CH3CH2CCH3 CH3 CH3 CH3CH2CHCH2CH3 CH3 or Ketone OH functional group Carboxylic acid functional group O O HO OH Back Forward Main Menu TOC Study Guide TOC Student OLC MHHE Website