b)查表y(Tc,P→0，π) YcH,0H=0.68,YH,=1.10,Yco=1.12 K,= YCHO 。2 1=0.502 YcoYin c)Ke= K号_1.079×103 =2.15×10-3 K. 0.502 10 10 b）查表 ( , ,) B TC PC 0.68, 1.10, 1.12 3 2  CH O H =  H =  CO = 0.502 2 2 3 = = CO H CH OH K     c） 3 3 2.15 10 0.502 1.079 10 − − =   = = r f P K K K  