Solution:Gas inside as system-Closed system (195-100)kg Remove the load suddenly>equilibrium broken>new equilibrium.No friction,but △L not quasi-equilibrium. 195kg A=100cn2 卫1h L=10cm First,state properties of 1 2: to-27℃Po-771unHg A=A+5=(7Ix1332Pa+ D ×98100 Pa=2.941x103Pa A 100 y=A×L=(0.01m2×0.1m)=0.001m3 A=n+5=(7Ix1332)Pa+ 195-100 Pa=1.960x103Pa 100 98100 AxL+AL)=0.01×(L+AL)=0.01mx0.1m+AQ ?? To be determined 上游究通大学 March 7,2019 12 SHANGHAI JIAO TONG UNIVERSITYMarch 7, 2019 12 Solution: Gas inside as system—Closed system First, state properties of 1 & 2: 1 5 1 b 195 (771 133.32) Pa 98 100 Pa 2.941 10 Pa 100 p F p A               Remove the load suddenly equilibrium broken new equilibrium. No friction, but not quasi-equilibrium. 2 3 1 V A L      (0.01 m 0.1 m) 0.001 m 5 2 b 2 195 100 (771 133.32) Pa 98 100 Pa 1.960 10 Pa 100 p p F A                2 2 V A L L L L            ( ) 0.01 ( ) 0.01 m (0.1 m+ L) 195kg (195-100)kg ?? To be determined